4[a-(3a-4)]=a+5

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Solution for 4[a-(3a-4)]=a+5 equation:


Simplifying
4[a + -1(3a + -4)] = a + 5

Reorder the terms:
4[a + -1(-4 + 3a)] = a + 5
4[a + (-4 * -1 + 3a * -1)] = a + 5
4[a + (4 + -3a)] = a + 5

Reorder the terms:
4[4 + a + -3a] = a + 5

Combine like terms: a + -3a = -2a
4[4 + -2a] = a + 5
[4 * 4 + -2a * 4] = a + 5
[16 + -8a] = a + 5

Reorder the terms:
16 + -8a = 5 + a

Solving
16 + -8a = 5 + a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1a' to each side of the equation.
16 + -8a + -1a = 5 + a + -1a

Combine like terms: -8a + -1a = -9a
16 + -9a = 5 + a + -1a

Combine like terms: a + -1a = 0
16 + -9a = 5 + 0
16 + -9a = 5

Add '-16' to each side of the equation.
16 + -16 + -9a = 5 + -16

Combine like terms: 16 + -16 = 0
0 + -9a = 5 + -16
-9a = 5 + -16

Combine like terms: 5 + -16 = -11
-9a = -11

Divide each side by '-9'.
a = 1.222222222

Simplifying
a = 1.222222222

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